X^2-15.4x+0.04=0

Solution for X^2-15.4x+0.04=0 equation:

X^2-15.4X+0.04=0

a = 1; b = -15.4; c = +0.04;
Δ = b2-4ac
Δ = -15.42-4·1·0.04
Δ = 237
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{237}=\sqrt{1*237}=\sqrt{1}*\sqrt{237}=1\sqrt{237}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15.4)-1\sqrt{237}}{2*1}=\frac{15.4-1\sqrt{237}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15.4)+1\sqrt{237}}{2*1}=\frac{15.4+1\sqrt{237}}{2}
$